Macro checks syntax before executing properly

While coding with mcfunctions, I used macros to simplify the code because it gets heavy really fast.

I was doing a loop that goes through the enderchest when I noticed it wasn't working as it should.

Here are the commands

execute unless score foo slotloop matches 0..26 run return 0

$execute as @a run data modify entity @e[name="storage",type=item_display,limit=1] item set from storage storage EnderItems[{Slot:$(slotloop)b}]
$execute as @a run item replace entity @s enderchest.$(slotloop) from entity @e[name="storage",type=item_display,limit=1] container.0
execute as @a run data modify entity @e[name="storage",type=item_display,limit=1] item set value {id:"minecraft:air",Count:1b}

scoreboard players operation foo slotloop += foo 1
execute store result storage variables slotloop int 1 run scoreboard players get foo slotloop

function player:func with storage variables

I theory, this code should go through all the slots then stop at 27 because It hits the return.

❌ While the code replaces the $(slotloop), it analyses the syntax at the same time, totally ignoring the first condition, making it not work.

Part of the debug code with the error:

[R = 27] scoreboard players operation foo slotloop += foo 1
[C] execute store result storage variables slotloop int 1 run scoreboard players get foo slotloop
[M] foo has 27 [slotloop]
[R = 27] execute store result storage variables slotloop int 1 run scoreboard players get foo slotloop
[C] function rayan223:bedwars/shop/load_menu/tmp with storage variables
[M] While instantiating macro rayan223:bedwars/shop/load_menu/tmp: Command 'execute as @a run item replace entity @s enderchest.27 from entity @e[name="storage",type=item_display,limit=1] container.0' caused error: Unknown slot 'enderchest.27'

To reproduce:

• create a datapack

• copy the code above and launch it with the following code

kill @e[name="storage",type=item_display,limit=1]
summon item_display ~ ~ ~ {CustomName:'{"text":"storage"}'}
scoreboard players set foo slotloop 0
scoreboard players set foo 1 1
execute store result storage variables slotloop int 1 run scoreboard players get foo slotloop
function player:func with storage variables

I could just replace the last line of the code with

execute unless score foo slotloop matches 27 run function player:func with storage variables

but the fact it is working that way isn't natural